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4a^2=5a+3
We move all terms to the left:
4a^2-(5a+3)=0
We get rid of parentheses
4a^2-5a-3=0
a = 4; b = -5; c = -3;
Δ = b2-4ac
Δ = -52-4·4·(-3)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{73}}{2*4}=\frac{5-\sqrt{73}}{8} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{73}}{2*4}=\frac{5+\sqrt{73}}{8} $
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